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Delicious77 [7]
3 years ago
11

Are these shapes congruent??

Mathematics
2 answers:
aniked [119]3 years ago
8 0

Answer:

No

Step-by-step explanation:

zimovet [89]3 years ago
3 0
No because one has four right angles while the other has one
Brainliest?
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1.) -12/6 is a natural, whole, integer, rational or irrational
Norma-Jean [14]

Answer:

Rational

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft
Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

P(X = x)  = ^nC_x  \ \beta^x   \  (1 - \beta)^{n-x}

where;

x = 0,1,2,...n    and    0  <  β   <   1

and x represents the  number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

P(X \ge 1) =  1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]

P(X \ge 1) =  1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0
3 years ago
Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.
vagabundo [1.1K]

Answer:

A) -2 - i√3 , -2 + i√3

Step-by-step explanation:

Solve using quadratic formula

x² + 4x + 7 = 0

The Almighty Formula

= -b ± √b² - 4ac/2a

Where ax + bx² + c = 0

From the above question

a = 1, b = 4, c= 7

Hence,

-4 ± √4² - 4 × 1 × 7/2 × 1

-4 ± √16 - 28/2

=( -4 ± √-12)/2

Since

b² - 4ac < 0

We have two complex roots

Simplifying

( -4 ± √-12)/2

= -4/2 ± √-12/2

= -2 ± 2√3i/2

= -2 ± √3i

Therefore,

-2 - √3i , -2 + √3i

or

-2 - i√3 , -2 + i√3

Option A , is the correct answer

3 0
3 years ago
is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120
marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is (x_1,y_1) and terminal point is (x_2,y_2), then the vector is

Vector=(x_2-x_1)i+(y_2-y_1)j

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

\overrightarrow v=(20-(-5))i+(60-22)j

\overrightarrow v=25i+38j       ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

\overrightarrow u=(75-50)i+(158-120)j

\overrightarrow u=25i+38j         .... (2)

From (1) and (2) we get

\overrightarrow u=\overrightarrow v

Therefore, vectors u and v are equal.

5 0
3 years ago
What is the length of the diagonal of the square shown below?
Tatiana [17]

Answer:

sqrt(50)

Step-by-step explanation:

Since it is a right triangle, we can apply the Pythagorem Theorem.

a^2 + b^2 = c^2

25 + 25 = c^2

50 = c^2

c = sqrt(50)

6 0
3 years ago
Read 2 more answers
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