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2 years ago

7

What is the slope of the lines segment with the endpoint (2,-5) and (-8,3)

1 answer:

lilavasa [31]2 years ago

3 0

Answer: - 0.8
Explanation I subtracted y2 and y1
(3-(-5) = 8
then subtracted x2 and x1
((-8) -2) =-10
Then I divide 8 and -10
And I got -0.8

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In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago

One wet weekend, 0.86 inches of rain fell on saturday. the next day, 1.52 inches of rain fell. how many inches of rain fell over

nataly862011 [7]

0.86 + 1.52 = 2.38 inches of rain fell over the weekend

4 0

2 years ago

Read 2 more answers

Please it’s an emergency

taurus [48]

Answer: C

Step-by-step explanation:

Okay first set a comparison since the two triangles are similar

x-1/20=x-1+27/3x+8

x-1/20 = x+26/3x+8

cross multiply

20x+520=3x^2+8x-3x-8

3x^2-15x-528=0

3(x^2-5x-176)=0

im kinda lazy to factor this out so i used an online calculator right here but factor it out like a good kid

x=16, x=-11

it has to be positive so x=16

C

6 0

2 years ago

3y+3 (1-y)-y=-6PLEASE help

Murrr4er [49]

3y+4+3y-y=-6
6y-y+4=-6
5y+4=-6
5y=-10
y=-2
If you have any questions let me know

7 0

2 years ago

Can someone please help me with my math homework

Natali5045456 [20]

Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles

time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)

Marcus travels 78000(2)(square) +32500(2)
= 84500yards
=48 miles

time = distance/speed
time=48/45
time=1.07 (1 hour 7 mins)

a)Josephine arrives first
b)she arrives earlier by 2 mins.

6 0

2 years ago