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bulgar [2K]
3 years ago
5

The formula for the nth term of the arithmetic sequence first term is 9 common difference is -2

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

a_n = 9 - 2(n-1)

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and is called common difference.

The nth term is given by the following equation:

a_n = a_1 + (n-1)d

In which a_1 is the first term and d is the common difference.

First term is 9 common difference is -2

This means that a_1 = 9, d = -2

So, the nth term is given by:

a_n = a_1 + (n-1)d

a_n = 9 + (n-1)(-2)

a_n = 9 - 2(n-1)

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In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

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