Find all integers x for which is a prime number. Show all work please!!!!

Mathematics

2 answers:

RSB [31]3 years ago

6 0

Answer:

4x Times the next point will be 11

Step-by-step explanation:

makes most sense mark as brainlst

OverLord2011 [107]3 years ago

4 0

Answer:

The answer to your question is

(x+4)(2x−1)

Step-by-step explanation:

You might be interested in

I WILL GIVE BRAINLIEST TO CORRECT ANSWER

pickupchik [31]

Answer:

Hi there! The correct option is the third one, aka $176050.

Step-by-step explanation:

median is the value in middle

low from high:

168800

172200

174500

177600

183700

191400

174500 and 177600 is the middle.

174500 + 177600 = 352100

352100/2 = 176050

8 0

3 years ago

Perform the indicated operation:

yaroslaw [1]

The expression $\frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }$ is equal to $\frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}$ .

<h3>How to simplify a composite algebraic expression</h3>

In this question we must use properties of <em>real</em> algebra to simplify a given expression as most as possible. We proceed to show each step with respective reason.

$\frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }$ Given
$\frac{m\cdot n \cdot (m^{2}-16\cdot n^{2})}{3\cdot m + 12\cdot n}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{c\cdot b}$
$\frac{m\cdot n \cdot (m-4\cdot n)\cdot (m+4\cdot n)}{3\cdot (m+4\cdot n)}$ Distributive property/ $a^{2}-b^{2} = (a +b)\cdot (a-b)$
$\frac{m\cdot n \cdot (m-4\cdot n)}{3}$ Existence of the multiplicative inverse/Modulative property
$\frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}$ Distributive property/ $x^a\cdot x^{b} = x^{a+b}$ /Result