H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
we have to find equation similar to

Firstly , we can divide both sides by 2


now, we can multiply both sides by 3

we get
............Answer
Answer:

Step-by-step explanation:

Plug in the 6 to the equations. Since B is the midpoint of AC, then both should be equal once plugged in [and solved].

Answer:
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Step-by-step explanation: