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seraphim [82]
3 years ago
13

If triangle ABC is dilated by a scale factor of 2.5 with a center of dilation at vertex B, how does the area of A'B'C' compare w

ith the area of ABC?
Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0
The area of A'B'C is 6.25 times the area of ABC. Also it wouldnt hurt the report the guy below who's obviously milking points.

Over [174]3 years ago
6 0

Answer:

The area of A'B'C' is 6.25 times the area of ABC.

Step-by-step explanation:

Got this right on USA test prep

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Consider the picture attached.

From right triangle trigonometry: 

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The length of the vector v can be determined using the Pythagorean theorem:

|v|= \sqrt{ 67^{2} + 15^{2} }= \sqrt{4489+225}= \sqrt{4714}=68.8


Thus, to make v a unit vector, without changing its direction, we need to divide v by |v|=68.8. 

This means that the x and y components will also be divided by 68.8, by proportionality.

So, the unit vector in the direction of v is:

<span>(67/68.8)i + (-15/68.8)j=0.97 i + (- 0.22)j
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Answer: 12.62°;  102.62°;  0.97 i + (- 0.22)j

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Step-by-step explanation:

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