Take the y and x and 4 as a common factor and you will get 4xy(2yz+3x) the second one is the answer
1) 2 with a small 4 at the top like an exponent
Answer:
3 pennies, 9 nickels, and 6 dimes
Step-by-step explanation:
We have three conditions:
(1) p + n + d = 18
(2) 0.01p + 0.05n + 0.10d = 1.08
(3) d = 2p
Multiply (2) by 100 and rearrange (3) to get a standard array.
(4) p + n + d = 18
(5) p + 5n + 10d = 108
(6) -2p + d = 0
Subtract (4) from (5). This gives
(4) p + n + d = 18
(7) 4n + 9d = 90
(6) -2p + d = 0
Multiply (4) by 2 and add to (6). This gives
(4) p + n + d = 18
(7) 4n + 9d = 90
(8) 2n + 3d = 36
Double (8) and subtract from (7). This gives
(4) p + n + d = 18
(7) 4n + 9d = 90
(9) 3d = 18
Divide (9) by 3. This gives
(10) d = 6
Substitute (10) into (7). This gives
4n + 9(6) = 90
4n + 54 = 90
4n = 36
(11) n = 9
Substitute (10) and (11) into (4). This gives
p + 9 + 6 = 18
p + 15 = 18
p = 3
Sasha has 3 pennies, 9 nickels, and 6 dimes.
It is: you use distribution method to solve the problem.
14m + 42 + 56m
Then you combine like terms:
14m + 56m + 42
Then you add
70m + 42 is your answer
cos(2<em>θ</em>) + sin²(<em>θ</em>) = 0
Half-angle identity:
cos(2<em>θ</em>) + (1 - cos(2<em>θ</em>))/2 = 0
Simplify:
2 cos(2<em>θ</em>) + 1 - cos(2<em>θ</em>) = 0
cos(2<em>θ</em>) = -1
Solve for <em>θ</em> :
2<em>θ</em> = arccos(-1) + 2<em>nπ</em>
2<em>θ</em> = <em>π</em> + 2<em>nπ</em>
<em>θ</em> = <em>π</em>/2 + <em>nπ</em>
where <em>n</em> is any integer.
