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2 years ago

How do I solve this problem step by step. -10( -4 - 2j

Mathematics

1 answer:

Phantasy [73]2 years ago

6 0

-10(-4-2j)
-10(-4)-10(-2j)
40+20j

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2 years ago

the sum of the first 6 terms of a geometric series is 15624 and the common ratio is 5. what is the first term of the series?

9966 [12]

Answer:

first term a=4

Step-by-step explanation:

Sum of the first 6 terms S6 = 15624

common ratio r= 5

n= 6

first term a=?

Formula: S6= a(r^n-1)/r-1

15624 = a( 5^6-1)/5-1

15624 = a(15625-1)/4

15624= a( 15624)÷4

15624= 15624a÷4

Cross multiply

15624×4 = 15624a

62496 = 15624a

divide both sides by 15624

62496÷15624 = 15624a÷15624

4 = a

a= 4

7 0

2 years ago

Help 15 points!!!!!!!!!!!!!!!!!!!!!

Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{7}{8}$ , then

∠ A = $tan^{-1}$ ( $\frac{7}{8}$ ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

AB² = BC² + AC² = 7² + 8² = 49 + 64 = 113 ( take square root of both sides )

AB = $\sqrt{113}$ ≈ 10.6 ( to the nearest tenth )

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2 years ago

(PLESE HELP) Factor the following expression. Simplify your answer.

mars1129 [50]

The factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

$5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$

Since $(p + 2)^{\frac{1}{3} }$ is common, we factor it out. So, we have

$(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2} + 4)$

Expanding the bracket, we have

$(p + 2)^{\frac{2}{3} } (5p(p^{2} + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

So, the factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0

1 year ago