A cycloalkane is a regular alkane with a ring or loop. An example is cyclohexane, which is a ring of 6 carbon atoms, each bonded to 2 hydrogen atoms
Concentration of solution: C=n/v
=> C=5mol/10L = 0.5mol/L
What do u mean P=? What is P?
For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
Sodium Flouride
Magnesium Nitrate
Calcium Phosphate
Sodium Oxide
Lead Iodide
Copper Sulphate
I've answered another one of your questions with the content of how to work these out
25 milliliters are required
