Answer:
The pH of the buffer solution = 8.05
Explanation:
Using the Henderson - Hasselbalch equation;
pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]
where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21
Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)
[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M
[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M
Therefore,
pH = 7.21 + log (0.663 / 0.096)
pH = 7.21 + 0.84
pH = 8.05
Answer:
solution concentration
Explanation:
Among the options given in the above question, solution concentration will affect the rate of a chemical reaction. This is because an increase in reagent concentration speeds up the reaction because there will be a greater number of reagent particles per unit volume, increasing the likelihood of effective collisions between them.
In addition to concentration, the factors that can influence the rate of a chemical reaction are temperature, catalyst, pressure and contact surface.
Answer is: Volume of hydrogen sulfide is 131,37 L.
m(H₂S) = 200,0 g.
n(H₂S) = m(H₂S) ÷ M(H₂S).
n(H₂S) = 200 g ÷ 34,1 g/mol.
n(H₂S) = 5,865 mol.
V(H₂S) = n(H₂S) · Vm.
V(H₂S) = 5,865 mol · 22,4 L/mol.
V(H₂S) = 131,37 L = 131,37 dm³.
n - amount of substance.
Vm - molar volume.
Answer:
b
Explanation:
The reaction that is not a displacement reaction from all the options is 
In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.
<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>
Correct option = b.
Sugar is the solute since it is the thing that is being dissolved.
And the water is the solvent since it is the thing that contains the solute.
