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emmainna [20.7K]
3 years ago
8

Assume the diameter of a neutral helium atom is 1.40 × 102 pm. Suppose that we could line up helium atoms side by side in contac

t with one another. How many atoms would it take to make the distance 6.20 cm from end to end?
Chemistry
1 answer:
Damm [24]3 years ago
5 0

Answer:

4.4285\times 10^8 many atoms would it take to make the distance 6.20 cm from end to end.

Explanation:

Diameter of the helium atom =  d=1.40\times 10^2 pm

Let the number of atoms required to make the distance 6.20 cm be n.

d\times n= 6.20 cm =6.20\times 10^{10} pm

1.40\times 10^2 pm\times n=6.20\times 10^{10} pm

n=\frac{6.20\times 10^{10} pm}{1.40\times 10^2 }=4.4285\times 10^8

4.4285\times 10^8 many atoms would it take to make the distance 6.20 cm from end to end.

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What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?
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Calculate the volume, in milliliters, for the following:
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Answer: The volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

  • As given moles of NaNO_{3} are 0.850 mol and molarity of NaNO_{3} solution is 0.5 M. Hence, its volume is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL

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  • As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol

So, volume for LiOH solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

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3 years ago
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