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emmainna [20.7K]
3 years ago
8

Assume the diameter of a neutral helium atom is 1.40 × 102 pm. Suppose that we could line up helium atoms side by side in contac

t with one another. How many atoms would it take to make the distance 6.20 cm from end to end?
Chemistry
1 answer:
Damm [24]3 years ago
5 0

Answer:

4.4285\times 10^8 many atoms would it take to make the distance 6.20 cm from end to end.

Explanation:

Diameter of the helium atom =  d=1.40\times 10^2 pm

Let the number of atoms required to make the distance 6.20 cm be n.

d\times n= 6.20 cm =6.20\times 10^{10} pm

1.40\times 10^2 pm\times n=6.20\times 10^{10} pm

n=\frac{6.20\times 10^{10} pm}{1.40\times 10^2 }=4.4285\times 10^8

4.4285\times 10^8 many atoms would it take to make the distance 6.20 cm from end to end.

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