You only have 15g of sodium to use for this reaction. how much copper(ii must you combine with the sodium to isolate the maximum
1 answer:
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Answer:
Number of times a one pound (2.2 kg) block of iron can be split in half before it stops being iron
= 84.29 times
Explanation:
Atoms : It is the smallest indivisible particle of the matter .
The atom can not be further breakdown .
Here in this question , we have to find the number of atoms (because it is the last possible situation for breaking of atom)
Mole : The quantity of the substance that contain as many particles as present in 12 g of C-12.It is quantity which Avogadro number(N0) of particles
<u>1.First calculate the number of moles of Fe in 2.2Kg Block</u>
Mass of Iron (Fe) = 55.845 amu
Molar mass of Iron = 55.845 g
Given mass = 2.2 kg
1 kg = 1000 g
2.2 kg = 2200 g
moles = 39.39
atoms
<u>3.Calculate Number of time(n), the block is </u><u>split into -Half </u>
Take log both side ,
Solve for n, you get
n= 84.29 (convert it to nearest whole number)
n = 84 times
Answer:
Explanation:
We're given the following ions:
Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.
Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:
Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:
Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide: