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Anna71 [15]
3 years ago
12

You only have 15g of sodium to use for this reaction. how much copper(ii must you combine with the sodium to isolate the maximum

amount of copper possible.
Chemistry
1 answer:
Eva8 [605]3 years ago
8 0
The balanced chemical reaction is:

<span>CuCl2 + 2Na → 2NaCl + Cu 

We are given the amount of sodium to be used up in the reaction. This will be the starting point for our calculations.

15 g Na ( 1 mol / 22.99 ) ( 1 mol Cul2 / 2 mol Na ) (134.45 g / 1 mol ) = 43.86 g CuCl2 needed to be able to obtain the maximum amount of copper.</span>
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How many protons , neutrons and electrons are in an atom of magnesium-24?
Minchanka [31]
Here is your answer:

Theirs 12 protons, 12 electrons, and 14 neutrons!

Reason: When you look at the atomic number for any element on the table with all of the elements that's how many protons, and electrons their are in the substance (or element) you find how many neutrons by rounding the number under the atomic number which will equal 14!

Your answer is 12:12:14
8 0
3 years ago
Which chemical is produced during vigorous exercise when the supply of oxygen is limited or inadequate?
Eduardwww [97]
It is lactic acid the chemical is produced during vigorous exercise when the supply of oxygen is limited or inadequate. <span> It forms when the body breaks down carbohydrates to use for energy during times of low oxygen levels. Hope this answers the question. Have a nice day.</span>
4 0
4 years ago
An aqueous solution of 10.03 g of catalase, an enzyme found in the liver, has a volume of 1.05 L at 27°C. The solution's osmotic
-Dominant- [34]

Answer : The molar mass of catalase is, 2.40\times 10^5g/mol

Explanation :

Formula used :

\pi =CRT\\\\\pi=\frac{w}{M\times V}RT

where,

\pi = osmotic pressure  = 0.745 torr = 0.000980 atm   (1 atm = 760 torr)

C = concentration

R = solution constant  = 0.0821 L.atm/mol.K

T = temperature  = 27^oC=273+27=300K

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution  = 1.05 L

Now put all the given values in the above formula, we get:

0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)

M=2.40\times 10^5g/mol

Therefore, the molar mass of catalase is, 2.40\times 10^5g/mol

7 0
3 years ago
How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?
pashok25 [27]

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol


x=(1.82*5)/1 = 9.10 mol CO2

4 0
3 years ago
Which of the following is not equal to 120 centimeters?
tia_tia [17]
<h3>Answer:</h3>

0.012 dekameters (dkm)

<h3>Explanation:</h3>

<u>We are given;</u>

  • 120 centimeters( cm).

Required to identify the measurements that is not equivalent to 120 cm.

  • Centimeters are units that are used to measure length together with other units such as kilometers(km), meters (m), millimeters (mm), dekameters (dkm), etc.
  • These units can be inter-converted to one another using suitable conversion factors.
  • To do this, we are going to have a table showing the suitable conversion factor from one unit to another.

Kilometer (km)

10

Decimeter (Dm)

10

Hectometer (Hm)\

10

Meter (m)

10

Dekameter (dkm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore;

To convert cm to km

Conversion factor is 10^5 cm/km

Thus;

120 cm = 120 cm ÷ 10^5 cm/km

            = 0.0012 km

To convert cm to dkm

Conversion factor is 10 cm/dkm

Therefore,

120 cm = 120 cm ÷ 10 cm/dkm

            = 12 dkm

To convert cm to m

The suitable conversion factor is 10^2 cm/m

Thus,

120 cm = 120 cm ÷ 10^2 cm/m

           = 1.2 m

To convert cm to mm

Suitable conversion factor is 10 mm/cm

Therefore;

120 cm = 120 cm × 10 mm/cm

            = 1200 mm

Therefore, the measurement that is not equal to 120 cm is 0.012 dkm

4 0
3 years ago
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