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2 years ago

100 POINTS AND BRAINLY NO LINKS What are the coordinates of point N after it is reflected across the x-axis?

Mathematics

2 answers:

erica [24]2 years ago

8 0

Answer: (-3, 4)

Explanation:

When you reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate is taken to be the additive inverse. The reflection of point (x, y) across the x-axis is (x, -y).

(-3, -4) ⇒ (-3, 4)

Tanzania [10]2 years ago

6 0

Answer:

(-3, 4)

Explanation:

Reflection over the x -axis is (x,y) → (x,−y)

Here the given point:

N(-3, -4)

If reflected:

(-3, 4)

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Theres 30 kilograms of 10% apple juice. How many kilograms of apples does it need to increase the current apple juice to 25%?

raketka [301]

The mass of the apple juice needed to increase the initial concentration to 25% is 45 kg

The given parameters;

Mass of the apple juice, m = 30 kg
current percentage, = 10%
final percent after increment = 25%

Let the mass added to increase the percentage to 30% = x

10% ----------------- 30 kg

25% ------------------ ?

$= \frac{25 \times 30}{10} \\\\= 75 \ kg$

The additional mass is calculated as;

$x+ 30 = 75\\\\x = 75 - 30\\\\x = 45 \ kg$

Thus, the mass of the apple juice needed to increase the initial concentration to 25% is 45 kg.

Learn more about percentage and ratio here: brainly.com/question/11752721

6 0

2 years ago

Factor the expression. 2x + 6

Naily [24]

Answer:

2+6

2(+3)

Solution

2(+3)

3 0

3 years ago

Read 2 more answers

Determine the value of a 10 year old car that costs $24,500 new and depreciates by 9% every year

son4ous [18]

First, we need to know how much the car depreciates each year. Multiply the price of the car by the percentage.

We can turn 9% into a decimal by moving the decimal point two places to the right.

9% = .09

24500 * .09 = 2205

Multiply the product by the amount of years you want to predict the price at.

2205 * 10 = 22050

Subtract that from the original price of the car.

24500 - 22050 = 2450

The value of a 10 year old car that costs $24500 and depreciates 9% every year will cost $2450.

7 0

3 years ago

Read 2 more answers

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

C. $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

Check the list of options for the expression on the left hand side

The correct answer is $(5-\frac{1}{2})^6$

3 0

3 years ago

7.6375 correct to 2 decimal place

ANTONII [103]

7.6375 =

1 Decimal Place = 7.6
2 Decimal Place = 7.64
3 Decimal Place = 7.638
4 Decimal Place = 7.6375

So the answer is 7.64 .
The 3 rounds up because 7 is bigger than 5...

5 0

3 years ago