All categories

3 years ago

1/3 (x-10) = -4 what is x

Mathematics

2 answers:

-BARSIC- [3]3 years ago

7 0

Step-by-step explanation:

1/3x-10/3=-4

1/3x=-4+10/3

1/3x=-2/3

x=-2

adell [148]3 years ago

5 0

Answer:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = −2

You might be interested in

What’s the gcf of 89 and 64

sergij07 [2.7K]

The greatest common factor is 1

7 0

3 years ago

Read 2 more answers

For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!

barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=\pi D$ or $C=2\pi r$

where

D is the diameter and r is the radius

therefore

$\pi =\frac{C}{D}$ or $\pi =\frac{C}{2r}$

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

The area of the circle is equal to

$A=\pi r^{2}$

therefore

The number pi is the ratio Area - radius squared

6 0

3 years ago

8x-20 - 3x-1 finding c

fomenos

What’s c? Not valid question

3 0

3 years ago

I HONESTLY NEED HELP!!

Natali5045456 [20]

Answer:

Step-by-step explanation:

an additional hour of walking is associated with an additional 0.7 mile walk

7 0

2 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

3 years ago