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fiasKO [112]
3 years ago
15

A cylinder has a base diameter of 14m and a height of 10m. What is its volume in cubic m, to the nearest tenths place?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

1539 cubic meters

Step-by-step explanation:

Hello, I can help you with this

to solve need  we will need these two equations

Step one

Remember

area of a circle

Area=\pi *\frac{diameter^{2} }{4}\\

Also, the volume of the cylinder

Volume= area of the circle * height

Volume=\pi *\frac{diameter^{2} }{4} *height\\

Step 2

put the values into the equation

Let

diameter= 14 m

height = 10 m

Volume=\pi *\frac{diameter^{2} }{4} *height\\\\Volume=\pi *\frac{(14\ m)^{2} }{4} *10\ m \\\\Volume=\pi *49\ m^{2} *10\ m\\Volume=1539.38\ cubic\ meters

I hope it helps,have a great day.

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But now we have 0.00090718 tons as well as 4 tons. Add those together and you get 4.00090718. Now, multiply this by 24. You get: 96.02177232.


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3 years ago
3x + 8 = -x + 20 What is x?
g100num [7]
First, lets take all the x values on one side.

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Now, lets put the numbers on the other side.

4x + 8 - 8 = 20 - 8
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5 0
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Igoryamba

Answer:

D

Step-by-step explanation:

The slope is 2/5 and the slope of the new line will be -5/2 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

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An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were
olga55 [171]

Answer:

Systematic sampling

Step-by-step explanation:

An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

For the contractor to effectively carry out the testing he has to employ a Non-probability system of sampling which is called Systematic sampling, because in systematic sampling we can assume the population size (x ) which in this case is 70 and the sample size( n ) to be 10

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7 0
3 years ago
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Alinara [238K]

Answer:

a) P(X \leq 4) = 0.6289

P(X < 4) = 0.4335

b) P(4 \leq X \leq 8) = 0.5452

c) P(X \geq 8) = 0.0511

d) 0.2605

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

It is important to know that the variance has the same value as the mean in a Poisson distribution. The standard deviation is the square root of the variance.

In this problem, we have that:

\mu = 4, \sigma = \sqrt{4} = 2.

To help our solution, i am going to find each of P(X = x) from x = 0 to 8[/tex]

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183

P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.0733

P(X = 2) = \frac{e^{-4}*4^{2}}{(2)!} = 0.1465

P(X = 3) = \frac{e^{-4}*4^{3}}{(3)!} = 0.1954

P(X = 4) = \frac{e^{-4}*4^{4}}{(4)!} = 0.1954

P(X = 5) = \frac{e^{-4}*4^{5}}{(5)!} = 0.1563

P(X = 6) = \frac{e^{-4}*4^{6}}{(6)!} = 0.1042

P(X = 7) = \frac{e^{-4}*4^{7}}{(7)!} = 0.0595

P(X = 8) = \frac{e^{-4}*4^{8}}{(8)!} = 0.0298

(a) Compute both P(X ≤ 4) and P(X < 4)

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0183 + 0.0733 + 0.1465 + 0.1954 + 0.1954 = 0.6289

---------

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0183 + 0.0733 + 0.1465 + 0.1954 = 0.4335

(b) Compute P(4 ≤ X ≤ 8).

P(4 \leq X \leq 8) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.1954 + 0.1563 + 0.1042 + 0.0595 + 0.0298 = 0.5452

(c) Compute P(8 ≤ X)

That is P(X \geq 8).

The sum of the probabilities must be 1 in decimal. Either X is greater or equal to 8, or X is lesser than 8.

So

P(X < 8) + P(X \geq 8) = 1

P(X \geq 8) = 1 - P(X < 8)

From what we have in a) and b)

P(X < 8) = P(X < 4) + P(4 \leq X < 8) = 0.4335 + 0.1954 + 0.1563 + 0.1042 + 0.0595 = 0.9489

So

P(X \geq 8) = 1 - P(X < 8) = 1 - 0.9489 = 0.0511

(d) What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation

One standard deviation is 2, and the mean is 4. So, this is:

P(4 < X \leq 6) = P(X = 5) + P(X = 6) =  0.1563 + 0.1042 = 0.2605

6 0
3 years ago
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