Remark
Sometimes you can avoid the distributive property. This is one of those cases. Start by dividing by 5. You can only do this is there a common factor between the left and right sides of the equal sign.
Solve
There is only 1 solution. If there was an x^2 somewhere, you would have 2 and if there was an x^3 there would be 3.
5(2x - 3) = 5 Divide both sides by 5
5(2x - 3)/5 = 5/5
(2x - 3) = 1 Remove the brackets.
2x - 3 = 1 Add 3 to both sides.
2x = 1 + 3
2x = 4 Divide by 2
x = 4/2
x = 2 <<<<< Answer
The answer to ur question is 2 7/8
Answer:
a) The dimensions of the rectangle are width = 34.64 and length = 34.64.
b)If one board is 2m long there needs to be 70 boards to enclose the whole ring.
Step-by-step explanation:
The area of a rectangle is given by:
area = width*height
In order to compute the amount of boards that will be needed to enclose the rink with the least cost we need to find the rectangle with area equal 1200 m² that has the smallest possible perimeter. This happens when the width and the height of the rectangle are equal, so we have:
area = width*width
1200 = width²
width² = 1200
width = sqrt(1200) = 34.64m
So the height and the with of the rink must be 34.64 m.
The perimeter of the rink is:
perimeter = 2*width + 2*height = 2*34.64 + 2*34.64 = 138.56 m
Since each board is 2m the amount of boards needed is given by the division of the perimeter by the length of the board. We have:
number of boards = 138.56/2 = 69.28
Since there won't be a 0.28 board, then the number must be rounded up to 70.
Answer: Its surface covers 1400 cm²
Explanation:
Since the length of painting = 40 cm
Breadth of painting = 35 cm
Since we know that area of rectangle is product of dimensions.
∴ Area of painting = length × breadth
= 40 cm × 35 cm
= 1400 cm²
∴ Its surface cover 1400 cm².