Diagonals of rhombus are perpendicular
area is (1/2)*d1 * d2 where d1 and d2 are the diagonal lengths
draw the diagonals on your rhombus and you will see a 30-60-90 triangle and then figure
sides will be 6 , 6√3 . 12
so d1 is 2*6 = 12
and d2 is 2*6√3 = 12√3
and area = (1/2)*12*12√3
= 72√3 square cm.
2kg is greater than 1kg if thats what you're asking
Answer:
Option (A)
Step-by-step explanation:
Measure of an angle formed between a chord and a secant is equal to the half of the difference of the intercepted arcs.
m(∠FEC) = ![\frac{1}{2}[m(\text{arc FC})-m(\text{arc})FD]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Barc%20FC%7D%29-m%28%5Ctext%7Barc%7D%29FD%5D)
(15 + 6x)° = ![\frac{1}{2}[(24x - 6)^{\circ}-(9+7x)^{\circ}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%2824x%20-%206%29%5E%7B%5Ccirc%7D-%289%2B7x%29%5E%7B%5Ccirc%7D%5D)
30 + 12x = (24x - 7x) - (6 + 9)
30 + 12x = 17x - 15
17x - 12x = 30 + 15
5x = 45
x = 9
m(∠FED) = (15 + 6x)
= 15 + 6(9)
= 69°
Option (A) will be the correct option.
The one is c okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
A.40,48 is the right answer