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3 years ago

Use the distributive property to write an equivalent expression. -(0-2)

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

Answer:

0+2 or simply 2

Step-by-step explanation:

just imagine a "1" by the minus

-1(0-2)

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The equation tan(55) = 15/b can be used to find the length of line AC.what is the length of line AC round to the nearest 10th 3.

Nadusha1986 [10]

Answer:

10.5 in

Step-by-step explanation:

Given

$tan(55) = \frac{15}{b}$

Required

Find length AC

The question is not detailed enough; so, I'll assume that b represents line AC.

Having said that;

We start by multiplying both sides by b

$tan(55) = \frac{15}{b}$

$b * tan(55) = \frac{15}{b} * b$

$b * tan(55) =15$

Divide both sides by tan(55)

$\frac{b * tan(55)}{tan(55)} = \frac{15}{tan(55)}$

$b = \frac{15}{tan(55)}$

Find tan(55)

$b = \frac{15}{1.42814800674}$

$b = 10.5031130731$

$b = 10.5$ <em>(Approximated)</em>

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Length AC is 10.5

7 0

3 years ago

Read 2 more answers

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago

PLEASEEEEEE HELP GUYS!!!!!

alexira [117]

The answer is 1.2m/s/s

3 0

3 years ago

Determine the amplitude or period as requested. Period of a y = - 1/3 * sin x - 1/3 pi/3 1/3 d 2pi

zysi [14]

Answer:

$Period = 2\pi$

Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

Required

Determine the period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = \frac{2\pi}{B}$

By comparing:

$y =A \sin(Bx + C) + D$ and $y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

$Bx = x$

So:

$B = 1$

So, we have:

$Period = \frac{2\pi}{B}$

$Period = \frac{2\pi}{1}$

$Period = 2\pi$

Hence, the period of the function is $2\pi$

6 0

3 years ago

In the figure below, Ken's company has placed sprinkler heads at the center of the two small semicircles. The radius

Novay_Z [31]

Answer:

The answer is below

Step-by-step explanation:

The sprinklers have a radius of 5 ft each. Since the larger semicircle (entire lawn) has a diameter that is formed from the 2 semicircles, therefore the radius of the larger semicircle is 10 ft.

Area that wont be watered can be gotten by subtracting the area of the two smaller circles from the area of larger semicircle.

Area that wont be watered = 1/2(π * 10²) - 2[1/2(π * 5²)] = 50π - 25π = 25π ft²

6 0

2 years ago