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vovikov84 [41]
3 years ago
10

Can somebody help with this no fake answers please im kinda low

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Step-by-step explanation:

let the total students be x then

25/100x=9

x=9×100/25

x=9×4

x=36

so total students are 36

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Writing the quation for a line that goes through the following points (0,3) (1,1
Tomtit [17]

\huge\boxed{y=-2x+3}

Start off by finding the slope of the line with the formula \frac{y_2-y_1}{x_2-x_1}.

Substitute the values. \frac{1-3}{1-0}

Subtract. \frac{-2}{1}

Simplify. -2

-2 is the slope of the line.

Now, use the point-slope formula to create an equation, where m is the slope and (x_1, y_1) is a known point on the line. y-y_1=m(x-x_1)

Substitute the values. y-3=-2(x-0)

Simplify. y-3=-2x

Move the 3 to create the final equation in slope-intercept form. \large\boxed{y=-2x+3}

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3 years ago
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4 years ago
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(WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST) Directed line segment is graphed below. Plot point R on the graph so that it spl
guajiro [1.7K]

Answer:

(0 , -1)

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WR = 4 + 2 = 6

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The same reason: RQ = 1/3 x RY = 1/3 x (5 + 4) = 3

Q (-4 , -4 + 3) i.e. (-4, -1)

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3 years ago
How many solutions if it is only one line?
Zielflug [23.3K]

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Step-by-step explanation:

3 0
3 years ago
Please help I really need help on this I would really appreciate it anything helps !
andreev551 [17]

Answer:

<em>AXE</em> and <em>CXD  </em>are vertical angles

<em>AXF</em> and <em>FXD  </em>are supplementary angles

<em>DXC </em>and <em>BXC  </em>are complementary angles

<em>EXA</em> and <em>AXB  </em>are adjacent angles

<em>AXC </em>and <em>CXD</em>  are supplementary angles

<em>EXD </em>and <em>AXC </em>are vertical angles

Step-by-step explanation:

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