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2 years ago

What is the next term of the arithmetic sequence? 3,9,15,

Mathematics

1 answer:

dimulka [17.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

3 + 6 = 9

9 + 6 = 15

15 + 6 = 21

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Three tenths times twelve

Sholpan [36]

Answer:

3.6

Step-by-step explanation:

0.3x12=3.6

Because you know that 12x3=36, so 12x0.3=3.6!

Good luck!

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2 years ago

Help meeee pleaseeeeee

Leto [7]

Answer: B, angle 1 and angle 7.

Step-by-step explanation: Of all the options provided, B is the only one where the the two angles are not congruent to each other. Also, same side interior angles are congruent, so...

5 0

2 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0

2 years ago

Help please! I will mark Brainiest!!

aleksklad [387]

Answer:

It is equal to each other

Step-by-step explanation:

$\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}$

6 0

2 years ago

Please help I'm really confused I need have with these 6 questions

Lelechka [254]

Ahh, basic shapes. Split up the weird shapes into easier ones. #1 can be truned into 2 trapezoids. #2 can be turned into 2 circles. #3 is a triangle and a trapezoid. #4 is 2 right triangles. #5 is a rectangel and a traingle. Finally, #6 is 3 traigles and a rectangle. Do you see how we broke the hard shapes into easier shapes?

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2 years ago