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vlada-n [284]
2 years ago
8

A video store charges

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

a. 10 + 2.50x

b. 60

c. 100

Step-by-step explanation:

a. 10 + 2.50x

b. 10 + 2.50(20)

= 10 + 50

= 60

c. 260 = 10 + 2.50x

250 = 2.50x

250/2.50 = x

x = 100

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The perimeter of a rectangle is 18 feet, and the area of the rectangle is 20 square feet. What is the width of the rectangle?
bogdanovich [222]

4 ft or 5 ft

i think thats right

7 0
3 years ago
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Please simplify, thank you
harina [27]

Answer: - 3/m^6

Step-by-step explanation: Simply the expression.

Hope this helps you!

8 0
3 years ago
What is the similarity ratio of ΔABC to ΔDEF?<br> Tri ABC: AC=4 CB=5<br> Tri DEF: DF= 2
alekssr [168]

The similarity ratio of ΔABC to ΔDEF = 2 : 1.

Solution:

The image attached below.

Given  ΔABC to ΔDEF are similar.

To find the ratio of similarity triangle ABC and triangle DEF.

In ΔABC: AC = 4 and CB = 5

In ΔDEF: DF = 2, EF = ?

Let us first find the length of EF.

We know that, If two triangles are similar, then the corresponding sides are proportional.

⇒ \frac{AC}{DF} =\frac{BC}{EF}

⇒ \frac{4}{2} =\frac{5}{EF}

⇒ 4EF=5\times2

⇒ EF=\frac{5\times 2}{4}

⇒ EF=\frac{5}{2}

Ratio of ΔABC to ΔDEF = \frac{AC}{DF} =\frac{4}{2}=\frac{2}{1}

Similarly, ratio of ΔABC to ΔDEF = \frac{BC}{EF} =\frac{5}{\frac{5}{2}}=\frac{2}{1}

Hence, the similarity ratio of ΔABC to ΔDEF = 2 : 1.

6 0
3 years ago
Can anyone help me with this, i just want to make surr i have it right. (20-4)×12-6. Does it equal 96 or 186
expeople1 [14]

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7 0
3 years ago
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Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
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