2 years ago

PLEASE HELP ME ASAP!!!!!!! TY! :)

Mathematics

2 answers:

Tamiku [17]2 years ago

6 0

Answer:

Step-by-step explanation:

zysi [14]2 years ago

4 0

Answer:

0 and 3

Step-by-step explanation:

bcoz do thatok u understand

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P( x) =x^3-6x^2-5x-14 What is the remainder R when the polynomial p(x) is divided by (x-7)

Igoryamba

Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

$\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}$ ⇒(1)

$\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}$ ⇒(2)

$\frac{2x-14}{x-7}=2$ ⇒(3)

From (1) , (2) and (3)

The quotient of the long division is $x^{2}+x+2$ and no remainder

So the remainder is zero

* If you want to check your answer Multiply the quotient by the divisor

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