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katovenus [111]
2 years ago
12

HELP PLEASE! Line segment DE is a midsegment of АВС Find the value of x.

Mathematics
1 answer:
Tanzania [10]2 years ago
7 0

Answer:

x=12

Step-by-step explanation:

It equals 12 because according to the midsegment theorem, the midsegment is 1/2 the value of the side it is parallel to.

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The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions
Salsk061 [2.6K]

Width = 5.5yd  

Length = 12yd

<u>Explanation:</u>

Area of rectangle =  66yd^{2}

Let width of the rectangle = b ,  

So, length = 2b+1  

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,  

Width = 5.5yd  

Length = 12yd

6 0
3 years ago
In spherical geometry lines are called _____
tester [92]

Answer:

the answer is: a great circle

5 0
3 years ago
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard devia
lesya692 [45]

Answer: P(x > - 0.23) = 0.41

Step-by-step explanation:

Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the readings at freezing on a batch of thermometers.

µ = mean temperature reading

σ = standard deviation

From the information given,

µ = 0°C

σ = 1.00°C

the probability of obtaining a reading less than -0.23°C is expressed as

P(x > - 0.23)

For x = - 0.23

z = (- 0.23 - 0)/1 = - 0.23

Looking at the normal distribution table, the probability corresponding to the z score is 0.41

7 0
3 years ago
James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

                                                 =\frac{27}{4} inches

Width of construction paper = 9 \frac{2}{3} inches

                                              = \frac{29}{3} inches

Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

                                             = \frac{261}{4} inches^2

Hence the area of the piece of construction paper is \frac{261}{4} inches^2

7 0
3 years ago
A bus covers 270km distance in 6 hours.
pentagon [3]

Answer:

(i)= 45 KPH, (ii) = 251 miles

Step-by-step explanation:

'Per' essentially means divide. Thus, to find Kilometres per hour, divide 270 by 6= 45. The bus is travelling at 45 KPH.

Then, to see how far a nine hour trip would cover, distance = speed * time =  251 miles.

7 0
1 year ago
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