Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
The answer is c. forgive me if i am wrong
The ball will hit the ground at 0.125 seconds
<h3>
Quadratic function</h3>
The equation of the function is a quadratic function, and the function is given as:
When the ball hits the ground, the value of h is 0.
So, the equation of the function becomes
Subtract 2t from both sides of the equation
Divide both sides by -2t
Divide both sides by 8
Hence, the ball will hit the ground at 0.125 seconds
Read more about quadratic functions at:
brainly.com/question/11631534
Answer:
As eq of line passing through 2 points is
y-y1 = (y2-y1)/(x2-x1) ][ x -x1)
where (X1,y1)( x2, y2) denotes points lying on line
substitute (X1 ,y1) by( -1,-2) and (X2,y2) by( 2,4)
y+2 = 6/3 )( x+1)
y+2= 2x +2
y = 2x is required equation