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Julli [10]
3 years ago
5

What is the value of x

Mathematics
1 answer:
topjm [15]3 years ago
6 0

Answer:

x=32

Step-by-step explanation:

Since all triangles in a triangle add up to 180, we can do 180-116=64. There are 2 more blank angles so we can divide 64 by 2 to get 32. I think that x is 32, but please correct me if I am wrong. Everybody makes mistakes.

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Which statements are true? Select the five correct answers.
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All except the last one

Step-by-step explanation:

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\sqrt{1.8}=1.34164079

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Solve this linear equation by graphing <br> 1/2x-y=4<br> 2y=x+6
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Answer:

see attachment for answer.

Step-by-step explanation:

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3 years ago
What is the solution to the equation 1^6 x = 2 ?
Dvinal [7]

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3 years ago
Which of the following could be the lengths of the sides of a 30 60 90 triangle?
lord [1]
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5 0
3 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
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