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1 year ago

I need help with this could some one help me understand

Mathematics

2 answers:

natka813 [3]1 year ago

7 0

Answer:4000

Step-by-step explanation:

because if 1in=500 miles then multiply 8 that will be 8in=4000 miles

because 5x8 is 40 just add the 2 zeros 4000 hope this helps

mixer [17]1 year ago

4 0

<h2>4000 miles (6,437.38 kilometers)</h2>

Since 1 inch is 500 miles on the map, 8 inches would be 8 times more than 500 miles.

In this problem, we have to use <u>multiplication method</u> to solve the problem.

Multiply 500 miles × 8 inches. In simplified manner:

500 × 8

We get the answer:

500 × 8 = 4000

Final result:

<h3>4000 miles</h3>

<em>Hope this helps :)</em>

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Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
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By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

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3 years ago

In AGHI, the measure of ZI=90°, GH = 96 feet, and IG = 25 feet. Find the measure of ZH to the nearest tenth of a degree.

iVinArrow [24]

Answer:

15.1

Step-by-step explanation:

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3 years ago

Dan saved twice as much as Brett. Maria saved $60 more than Brett. If they saved $600 altogether, how much did Maria save?

givi [52]

Setting it up, we have Dan + Bret + Maria all saving 600.00
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3 years ago

Read 2 more answers

Someone please help me

xxTIMURxx [149]

I think its 6 i'm not sure hope this might help

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3 years ago

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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3 years ago