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Elis [28]
3 years ago
13

PLEASE HELP ME WITH THESE TWO QUESTIONS!! BRAINLEIST

Mathematics
2 answers:
Alex17521 [72]3 years ago
5 0

Answer:

Okay, i will help you on those.

Step-by-step explanation:

Can you give me brainliest on this question? ty :D

PtichkaEL [24]3 years ago
3 0
What is the question
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Assume every 10-digit natural number is a possible telephone number except those that begin with 0, 1 or 2. What fraction of tel
lana [24]

Answer: 1/70

Step-by-step explanation:

This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.

Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,

then the probability of figure "8" starting phone number = 1/7

Since all 10 numbers can possibly end a phone number,

then the probability of having figure "8" as the last digit of a phone number = 1/10

Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.

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3 years ago
What is the measurement of
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Answer:

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3/4 is 1/3 of what number? Write a division expression to match this expression
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It would be 9/4. To find 1/3 of something you have to multiply it by 3. 9/4 should be considered as a division expression. Hope this helped!
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