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AlexFokin [52]
3 years ago
7

Ian has 14 boxes of paper and divides them evenly between 4 coworkers. How many whole boxes did each coworker

Mathematics
1 answer:
denis-greek [22]3 years ago
6 0

Each co-worker can get 3 whole boxes, there is one half left over

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Solve the equation 4=t/2.5
larisa [96]

the answer would be 10 because you have to times by 2.5 on both sides to get t on its own.

4 × 2.5 is 10

6 0
3 years ago
Read 2 more answers
Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What
White raven [17]

Answer:

Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18Jynessa wants to order these fractions: StartFraction 4 over 9 EndFraction, two-thirds, one-sixth, Negative 2 and one-half. What should she use as her common denominator? 6 9 12 18

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Here is a list of the normal monthly precipitation (in inches) for January for 20 different U.S. cities. 4.0, 1.0, 1.5, 1.6, 2.0
shutvik [7]

Answer:

minimum value = 1.0 , the lower quartile = 2.3, the middle value = 3.5.

the upper quartile = 3.95, the maximum value  = 7.3.

Step-by-step explanation:

Five Number Summary of any data consists basically of 5 data sets.

1) The minimum Value

2)The first (lower) quartile

3) The middle value (Median)

4) The third (upper) quartile

5)The maximum value

Now, the given data is  4.0, 1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.1, 5.8, 4.1, 7.3

Arrange it in the ascending order,

1.0, 1.5, 1.6, 2.0, 2.2, 2.4, 2.7, 3.4, 3.4, 3.5, 3.6, 3.6, 3.7, 3.7, 3.9, 4.0, 4.1, 4.1, 5.8, 7.3

Here,

1) The minimum Value  is 1.0

2)The first (lower) quartile  is  2.3.

3) The middle value (Median)  is 3.5.

4) The third (upper) quartile is  3.95.

5)The maximum value  is 7.3.

7 0
4 years ago
If a function f(x)=x^3 has the domain {-3,0,2,4} what is it's range
torisob [31]
27, 0, 8, 64
All u need to do is cube all the numbers in the domain
4 0
3 years ago
Read 2 more answers
A plant manufactures part whose lengths are normally distributed with a mean of 16.3 centimeters and a standard deviation of 2.5
EastWind [94]

The probability that the plant manufactures a part between 10.8 and 12.8 centimeters 13%

<h3>How to find the probability that the part is between 10.8 and 12.8 centimeters</h3>

The probability is solved z scores, this measures the amount of standard deviation sample X is from mean. the formula is below

z = (X - μ) / σ

<u>Definition of variables</u>

mean, μ = 16.3 centimeters

standard deviation, σ = 2.5 centimeters

X = 10.8 and 12.8 centimeters

z score, z

substituting into the formula

for X = 12.8 centimeters

=  (X - μ) / σ

= (12.8 - 16.3) / 2.5

= -1.4

the p value for z of -1.4 = 0.161513

for X = 10.8 centimeters

=  (X - μ) / σ

= (10.8 - 16.3) / 2.5

= -2.2

the p value for z of -2.2 = 0.027807

the probability is calculated as below

0.161513 - 0.027807= 0.133706

= 0.13

=13%

Learn more about standard deviation at:

brainly.com/question/28948351

#SPJ1

8 0
1 year ago
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