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nikdorinn [45]
2 years ago
11

Okay I have reposted the question. Please help me ASAP

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
5 0

Answer:

angle 9

Step-by-step explanation:

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-8(2b-7)-9(b-5)<br>simplify ​
GenaCL600 [577]

Answer:

<h2>-25b + 101</h2>

Step-by-step explanation:

-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101

3 0
3 years ago
Read 2 more answers
How many solutions does the equation -2 + 2y + 3 =3 have
jeka94

Answer: y = 1

so 1! hopefully I helped!

Step-by-step explanation:

7 0
3 years ago
2. What is the variable in the expression:<br> 13x3 +7<br> (Select one answer)<br> 7<br> 3<br> 13
sdas [7]
I think it would be 3
3 0
2 years ago
Rigo and Ian went shopping for soccer cleats and practice uniforms. Rigo spent $451, before taxes, and purchased three uniforms
yan [13]

Answer:

The price of uniform U= $145

price of each pair of cleats C= $16

Step-by-step explanation:

Let:

The Price of Each Uniform = U

The Price of Each Pair of Cleats = C

Rigo spent $451, before taxes, and purchased three uniforms and one pair of cleats.

→ Equation A

Ian spent $757, before taxes, and purchased five uniforms and two pair of cleats.

→ Equation B

Let's calculate → 2(Equation A) - (Equation B)

2(3U+C)-(5U+2C)= 2(451) -757

6U+2C-5U-2C= 145

U=$ 145

3U+C= 451

3(145)+C= 451

C= 451-435

C= $16

3 0
3 years ago
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0
3 years ago
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