Answer:
the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Step-by-step explanation:
From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.
Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:







Thus; the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
The formula for the discriminant is the square root of b^2 - 4ac
8x^2+18x-5= 0
a = 8, b=18, c= -5
Square root of 324 +160
Square root of 484 = 22 The discriminant is 22
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.