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jonny [76]
3 years ago
9

HELP 10 POINTS AND BRAINLIEST The triangles below are similar. In each traingle there is a 53°angle and a right angle. What is t

he measure of the third angle in each triangle?
37º
47º
53º
127º

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Since both triangles are similar, we know this because they have 2 angles in common, they both have the same third angle.

To find the third angle, we use the angle sum. The sum of angles in a triangle will always equal 180 degrees. We are given a right angle which is 90 degrees and another angle, which is 53 degrees. Knowing this:

90 + 53 + x = 180 (I have chosen to call the third angle x)

when rearranging this we get

180 - 90 - 53 = x

now we solve

x = 37 degrees

Hope this helps,

Cate

Andrei [34K]3 years ago
8 0

Answer:

37°

Step-by-step explanation:

Their size is irrelevant.

Since we know that the two other angles are 53° and 90°, we know that the last angle is 37° (180-53-90).

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Answer:

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Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

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\mathbf{ YX = \sqrt{9+36} }

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\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

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