Answer:
sorry bro u need some point in the questions
Answer: The diagonals of a parallelogram bisect each other. Steps (a), (b), and (c) outline proof of this theorem. (See Exercise 25 for a particular instance of this theorem.) (a) In the parallelogram OA BC shown in the figure, check that the coordinates of must be (b) Use the midpoint formula to calculate the midpoints of diagonals and (c) The two answers in part (b) are identical. This shows that the two diagonals do indeed bisect each other, as we wished to prove. (FIGURE CAN'T COPY)
Question 1:
Add all the ratio numbers.
2+6+7=15
Now, divide that from 45, which is the given perimeter
45/15=3
Now, multiply the whole ratio by 3.
6:18:21
The shortest side is 6 inches.
Question 2:
Add all the ratio components.
17+16+12=45
Divide that by 180, the total degrees in a triangle.
180/45=4
Multiply that with 17 (largest ratio component).
You get 68, which is your answer.
Question 3:
(2x+7)/(3x-4) = 11/2
This proportion is quite simple and can be solved by setting the numerator equal to the numerator and the denominator equal to the denominator.
2x+7=11
3x-4=2
If you solve both of these, the value of x is 2.
That's your answer.
(Note: this is only a special case where you can do this)
Hope this helps! :)
Answer:
2x+5=12
Step by-step explanation:
2x+5=12
Subtract 5
2x=7
Divide each side by 2
x=3.5
Answer:
Answer: LA=2π rh
Hope this helps! Please mark me Brainliest if it did! Have a nice day!
Step-by-step explanation: