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3 years ago

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Mr. Lloyd wants to build a dollhouse for a starter this is a proportional to their house he might have to live in this house and

12 ft by 16 ft what will the dimensions of living room if every foot of the actual house is equal to 1/2 inch doll house

1 answer:

Kaylis [27]3 years ago

3 0

Answer:

12’ x 16’ = 6 in * 8 in

Step-by-step explanation:

Allow me to revise your question for a better understanding.

<em>Mr. avoid wants to build a doll house for his daughter that is proportional to their house you measure the living room of his house and it was 12’ x 16’ what will the dimensions of the doll house living room if every foot of the actual house equals 1/2 inch in the doll house </em>

My answer:

Given:

The living room of his house was 12’ x 16’ and this is the actual house

The dimensions of the doll house living room if every foot of the actual house equals 1/2 inch is:

<=> 1 foot = 1/2 inch

=> the dimensions of the doll house living room is:

12’ x 16’ = 6 inch * 8 inch

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A culture of bacteria has an initial population of 41000 bacteria and doubles every 5 hours. Using the formula P_t = P_0\cdot 2^

vodomira [7]

Answer:

285541

Step-by-step explanation:

According To The Question,

Given, A culture of bacteria has an initial population of 41000 bacteria and doubles in every 5 hours & $P_{t} = P_{i}*(2)^{\frac{d}{t} }$ .

Now, for the population of bacteria in the culture after 14 hours is $P_{t}$ . We have Initial Population( $P_{i}$ )=41000 , d=14 & t=5 .

Put These Value in Above Formula, We get

$P_{t} = 41000*(2)^{\frac{14}{5} }$

$P_{t} = 41000*2^{2.8}$

$P_{t} = 41000*(6.9644)$

$P_{t} =$ 285540.5847 ≈ 285541

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3 years ago

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Korolek [52]

2 and 1/4 miles is how far Mary walks around the track. This is because she walks for 15 minutes before Jerry gets there, which is 0.75 miles at 3mph. Then Jerry goes for 2 miles, which is half an hour. Half an hour is double 15 minutes, so it's double 0.75 miles. So 0.75 plus 1.5 = 2.25 Mark me brainliest :3

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3 years ago

The circumference of circle a is 3 times greater than the circumference of circle

Liono4ka [1.6K]

We know, Circumference of a Circle = 2πr

In mathematical form, You can write it as:
2πr₁ = 3(2πr₂)

2π(12) = 6πr₂

24π = 6πr₂

r₂ = 4 m

In short, Your Answer would be: 4 meter

Hope this helps!

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3 years ago

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is

$P_{16} = \left(\frac{109}{100}\right)^{16}P_{0} = (1.09)^{16}P_0 = 3.97\cdot 200000 \approx 794062$

d) In this case we want to know when $P_n>400000$ , which is equivalent to

$(1.09)^{n}P_0>400000$ .

Substituting the value of $P_0$ , we get

$(1.09)^{n}200000>400000$ .

Simplifying the expression:

$(1.09)^{n}>2$ .

So, we need to find the value of $n$ such that the above inequality holds.

The easiest way to do this is take logarithm in both hands. Then,

$n\ln(1.09)>\ln 2$ .

So, $n>\frac{\ln 2}{\ln(1.09)} = 8.04323172693$ .

So, the population of Tacoma should exceed the 400 000 by the year 2009.

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3 years ago

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What is 2(5)+3(4)+5^2? (The ^ means the exponent)

castortr0y [4]

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