How many of possible outcomes could be a number biggger than 6 on either cube
1 answer:
You might be interested in
Hi there!
• f(x) = 3x + 1
• g(x) = x² - 6
Then,
According to th' question :-
(f - g)(x) = f(x) - g(x)
= 3x + 1 - (x² - 6)
= 3x + 1 - x² + 6
= -x² + 3x + 7
Hence,
Option 2ⁿᵈ : -x² + 3x + 7 is Correct.
~ Hope it helps!
• f(x) = 3x + 1
• g(x) = x² - 6
Then,
According to th' question :-
(f - g)(x) = f(x) - g(x)
= 3x + 1 - (x² - 6)
= 3x + 1 - x² + 6
= -x² + 3x + 7
Hence,
Option 2ⁿᵈ : -x² + 3x + 7 is Correct.
~ Hope it helps!