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Alexus [3.1K]
3 years ago
6

8 1/5-2 7/8 Fractions math

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

5  13 /40

Step-by-step explanation:

hope this helps :))

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On which interval is the function increasing? ​
sukhopar [10]

Answer:

b. (-1,0)\cup (1,\infty)

Step-by-step explanation:

The graph can be divided into 4 regions.

Region 1 is for x\in (-\infty,-1)

Region 2 is for x\in (-1,0)

Region 3 is for x\in (0,1)

Region 4 is for x\in (1,\infty)

So, for the region 1, the values of y goes on decreasing with increasing x. Therefore, the function is decreasing in the interval (-\infty,-1).

Now, for the region 2, the values of y increases with increasing x. So, the function is increasing in the interval (-1,0).

For the region 3, the the values of y goes on decreasing with increasing x. Therefore, the function is decreasing in the interval (0,1).

Now, for the region 4, the values of y increases with increasing x. So, the function is increasing in the interval (1,\infty).

Therefore, regions 2 and 4 are the regions when the function is increasing.

Hence, the correct option is b. (-1,0)\cup (1,\infty)

8 0
3 years ago
Jon decides to take his seven year old son to the movies. The price for the child's ticket is 3.75 dollars less than the price f
Rama09 [41]
X + 3.75 = adult ticket
x + 3.75 = a
4 0
4 years ago
Can anyone take me through the steps of my problem? : 43.95 divide 16.1
Lynna [10]

Answer:

2.72 is the shortened version.

Step-by-step explanation:

for the step by step explanation

go to this link below

https://www.calculatorsoup.com/calculators/math/longdivisiondecimals.php

(copy the bold stuff, go to a new tab, paste it on the search, the search it up)

Hope I helped you find the answer to your question!!!  ^_^

3 0
3 years ago
Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?
Feliz [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see

\bf h(x)=-x+5\implies h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\stackrel{D}{+5}

a shift down by 3 units, means a vertical shift downwards, so D needs to drop by 3 units.

\bf h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\boxed{\stackrel{D}{+5-3}}\implies h(x)=-1(1x+0)+2
\\\\\\
h(x)=-x+2
4 0
3 years ago
A man walks iinto a store with 25.50 and walks out with 5.25 how much did he spend?
san4es73 [151]
He spent exactly 20.25, so it's A.
7 0
3 years ago
Read 2 more answers
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