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3 years ago

8 1/5-2 7/8 Fractions math

Mathematics

1 answer:

pishuonlain [190]3 years ago

7 0

Answer:

5 13 /40

Step-by-step explanation:

hope this helps :))

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On which interval is the function increasing?

sukhopar [10]

Answer:

b. $(-1,0)\cup (1,\infty)$

Step-by-step explanation:

The graph can be divided into 4 regions.

Region 1 is for $x\in (-\infty,-1)$

Region 2 is for $x\in (-1,0)$

Region 3 is for $x\in (0,1)$

Region 4 is for $x\in (1,\infty)$

So, for the region 1, the values of $y$ goes on decreasing with increasing $x$ . Therefore, the function is decreasing in the interval $(-\infty,-1)$ .

Now, for the region 2, the values of $y$ increases with increasing $x$ . So, the function is increasing in the interval $(-1,0)$ .

For the region 3, the the values of $y$ goes on decreasing with increasing $x$ . Therefore, the function is decreasing in the interval $(0,1)$ .

Now, for the region 4, the values of $y$ increases with increasing $x$ . So, the function is increasing in the interval $(1,\infty)$ .

Therefore, regions 2 and 4 are the regions when the function is increasing.

Hence, the correct option is b. $(-1,0)\cup (1,\infty)$

8 0

3 years ago

Jon decides to take his seven year old son to the movies. The price for the child's ticket is 3.75 dollars less than the price f

Rama09 [41]

X + 3.75 = adult ticket
x + 3.75 = a

4 0

4 years ago

Can anyone take me through the steps of my problem? : 43.95 divide 16.1

Lynna [10]

Answer:

2.72 is the shortened version.

Step-by-step explanation:

for the step by step explanation

go to this link below

https://www.calculatorsoup.com/calculators/math/longdivisiondecimals.php

(copy the bold stuff, go to a new tab, paste it on the search, the search it up)

Hope I helped you find the answer to your question!!! ^_^

3 0

3 years ago

Consider the graph of the linear function h(x) = –x + 5. Which could you change to move the graph down 3 units?

Feliz [49]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see

$\bf h(x)=-x+5\implies h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\stackrel{D}{+5}$

a shift down by 3 units, means a vertical shift downwards, so D needs to drop by 3 units.

$\bf h(x)=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+0})\boxed{\stackrel{D}{+5-3}}\implies h(x)=-1(1x+0)+2
\\\\\\
h(x)=-x+2$

4 0

3 years ago

A man walks iinto a store with 25.50 and walks out with 5.25 how much did he spend?

san4es73 [151]

He spent exactly 20.25, so it's A.

7 0

3 years ago

Read 2 more answers