$\bf (x-2)^{2\div 3}=49\implies (x-2)^{\frac{2}{3}}=7^2\implies \stackrel{\textit{raising both sides by }\frac{3}{2}}{\left( (x-2)^{\frac{2}{3}} \right)^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}} \\\\\\ (x-2)^{\frac{2}{3}\cdot \frac{3}{2}}=7^3\implies (x-2)^1=7^3\implies x=7^3+2\implies x=345$

4 0

3 years ago

Divide x^3+2 by x+1 long division ppleeease! :)

anzhelika [568]

Long division: (x³ + 2) ÷ (x + 1)

 x² – x + 1 
x³ + 0x² + 0x + 2 | x + 1
– x³ – x² ⋮ ⋮
– x² + 0x ⋮
+ x² + x ⋮
+ x + 2
 – x – 1
+ 1

 Quotient: Q(x) = x² – x – 1;

Remainder: R(x) = + 1.

I hope this helps. =)

3 0

3 years ago

After the addition of an acid, a solution has a volume of 90 milliliters. The volume of the solution is 3 milliliters greater th

11111nata11111 [884]

Answer: $21.75\ milliliters$

Step-by-step explanation:

Let be "x" the original volume of the solution (in milliliters) before the acid was added and "y" the volume of the solution (in milliliters) after the addition of the acid.

Set up a system of equations:

$\left \{ {{x+y=90} \atop {y=3x+3}} \right.$

Applying the Substitution Method, you can substitute the second equation into the first equation and then solve for "x":

$x+y=90\\\\x+(3x+3)=90\\\\4x+3=90\\\\x=21.75$

6 0

3 years ago