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andrew-mc [135]
3 years ago
10

In a "torture test" a light switch is turned on and off until it fails. if the probability that the switch will fail any time it

is turned on or off is 0.001, what is the probability that the switch will fail after it has been turned on or off 1,200 times?
Mathematics
1 answer:
Alex777 [14]3 years ago
6 0
The probability that the switch does not fail is 1-0.001=0.999. In order to switch the lights off and on 1200 times, we need to press the switch 2400 times. Each event is assumed independent from the others; when we press the switch, its probability that it will fail is not influenced by the previous pressing of the switch. Thus, the probability that it won't fail after 2 times is 0.999*0.999=0.999^2. Similarly, we get that the required probability is : P=0.999^{2400}=0.091
This is a relatively low probability. We see that even if the probability that the switch fails one time is very low, after many repetitions it becomes quite probable that the switch will fail at least one time.
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Step-by-step explanation:

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Find the equation of the line passing through point (-1, -2) and having <br> slope 1/5. Show work.
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Step-by-step explanation:

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lukranit [14]

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3 years ago
Which phrases can be used to represent the inequality 12-3x≥9? Check all that apply. (multi choice)
balandron [24]

Answer:

Which phrases can be used to represent the inequality 12-3x≥9? Check all that apply. (multi choice)

<u> A Twelve less than three times a number is greater than or equal to nine. </u>

B Twelve less than three times a number is at least nine.

C Twelve less three times a number is at least nine.

D Twelve minus the product of three and a number is no more than nine.

E Twelve less three times a number is at most nine.

F Twelve minus the product of three and a number is no smaller than nine.

G Twelve minus the product of three and a number is larger than nine.

Step-by-step explanation:

12 - 3x>=9

8 0
3 years ago
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
3 years ago
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