Answer:
49π cm²
Step-by-step explanation:
Diameter (d) = 14 cm
Radius (r) = d/2 = 14/2 = 7 cm
Area of a circle
= πr²
= π × (7)²
= 49π cm²
Hope it helps ⚜
Q: You are shot out of a cannon at the fair. The equation y=-1/5 * (x+2) (x-28) models your flight path, where y is the height above the ground and x is the horizontal distance. Which of the following statements in the comments are true?
a) You reach a maximum height of 45 feet,
b) You will land 11.2 feet from the cannon,
c) The barrel of the cannon is about 11 feet above the ground.
d)At a point 13 feet from the cannon, you begin to descend.
A: When y = 0, x = 28
y’ = 0 at x = 13 where Y is max = 15^2 / 5 = 45
Hence a is true, b is false, c is false, d is false .
Answer:
- 7-5 => 2
- -7+5 => -2
- -7-5 => -12
- 7-(-5) => 12
Step-by-step explanation:
Lets solve the expressions one by one
<u>1. 7-5</u>
we can see that it is simple subtraction. A smaller number is being subtracted from a large number.
So the answer is 2
<u>2. -7+5</u>
There are two numbers with different signs. When there is a number with plus and a number with minus both quantities are subtracted but the larger quantity determines the sign of the answer.
In this case, 7 is larger and has negative sign, the answer will be -2
<u>3. -7-5</u>
When there are two numbers with minus sign they are added but the answer has the minus sign with it.
So the answer will be: -12
<u>4. 7-(-5)</u>
When minus is multiplied with minus it converts to positive
So

Hence,
- 7-5 => 2
- -7+5 => -2
- -7-5 => -12
- 7-(-5) => 12
I suppose you mean

Recall that

which converges everywhere. Then by substitution,

which also converges everywhere (and we can confirm this via the ratio test, for instance).
a. Differentiating the Taylor series gives

(starting at
because the summand is 0 when
)
b. Naturally, the differentiated series represents

To see this, recalling the series for
, we know

Multiplying by
gives

and from here,


c. This series also converges everywhere. By the ratio test, the series converges if

The limit is 0, so any choice of
satisfies the convergence condition.
That means the same as 3-17 so the answer is -14