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cupoosta [38]
3 years ago
13

Can someone help me please thank you

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

C,D, and E

Step-by-step explanation:

Markup means to raise the price. Multiplying by anything grater than 1 is a markup and since C,D, and E are all multiplying the price of W by greater than one they are all marking up.

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What percentage of data points do the two whiskers<br> contain?<br> 25%<br> 30%<br> 50%<br> 75%
Virty [35]

Answer:

The answer is C. 50%

Step-by-step explanation:

I'm doing the same thing and it's right. Trust me:)

8 0
3 years ago
Luna is going bowling. Shoe rental cost $3 and the lane cost $2 per game. If Luna paid a total of $17, how many games did she bo
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3 0
2 years ago
A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
How do u round 23.897 to the nearst 9
Stella [2.4K]
Do you mean the nearest 10th
7 0
3 years ago
7 × 30 = 7 × ___ tens
Mariulka [41]
30 tens so that it can still= 210 tens.
3 0
3 years ago
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