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SashulF [63]
2 years ago
10

8203 divided by 31 with remainder!!!​

Mathematics
1 answer:
BabaBlast [244]2 years ago
5 0
The answer is 264 1/6
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If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
Ierofanga [76]
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
</span>hence proved


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