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3 years ago

Fred buys flags from a manufacturer for f dollars each and then sells the flags in his store for a 26%markup.

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

Answer:

the markup is 1.26 (the amount added is .26)

1.26x (when x is the price Fred buys them for from the manufacturer)

1.26(40)

$50.40 is the retail price

50.4-40

$10.40 is the markup

Step-by-step explanation:

The 26% markup means that he is selling the flags 26% above the cost.

So, the cost would represent 100%, which is 1, and 26% of markup in decimal number is 0.26.

The price including the markup would be 1.26 as decimal or 126% as percentage.

The problem states that the cost is unknown, so we represent that with a variable x. The retail price would be 1.26x, which is 126% per flag.

Finally, if Fred paid $40 per flag, the actual retail price would be:

1.26($40)=$50.40.

With $10.40 of markup.

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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

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Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

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