It is easiest to simply just substitute any of the choices into the original equation and see which one satisfies the equation.
Given the equation: 3 * |5 + x| = 12
Using choice A. x = 7
3 <span>* |5 + 7| = 12
</span>36 =/= 12
Using choice B. x = 1
3 <span>* |5 + 1| = 12
</span>18 =/= 12
Using choice C. x = -9
3 <span>* |5 + -9| = 12
</span>12 = 12
Therefore, the correct answer is C. -9
It is given that the bottle temperature begins at the freezer temperature of –16° C. Thus, the initial temperature is –16° C.
Now, sitting on the kitchen counter, the bottle temperature will go up a steady 9.6° C every hour. We need to know how many hours will it take to reach 20° C.
Let us assume that it will take "" hours to reach the required temperature. Then the equation that will guide this system will be a linear one as shown below:
Adding 16 to both sides we get:
Dividing both sides by 9.6 we get:
hours
Thus it will take 3.75 hours (or 3 hours 45 minutes) for the bottle of maple syrup to reach a temperature of celsius.
Answer:
Step-by-step explanation:
Start by drawing out the triangle on the graph:
(See picture)
(By the drawing you can judge me that I am a really bad artist)
Theta and the side lengths are labeled, the hypotenuse has a length of √21 by Pythagora's theorem. Now, time to put everything to the trigonometric functions:
(Suppose that x is theta as I can't type it)
By some basic understanding that's all that I can do.
To find the answer of this, you would need to find the lcm (lowest common multiple) The lcm of 6 and 4 is 24
SO you would need to multiply both fractions to get the denominator to 24
1/6 times 4 =4/16 1/4 times 6=6/24
Therefore 1/4 is greater
Answer:
Reflective
Symmetric
Transitive
Step-by-step explanation:
A is reflexive: Since the relation is based on the sum of characters in a string, s=s, so sAs.
A is symmetric: Suppose s and t are strings. if sAt, then s and t have the same sum of their characters, so tAs.
A is transitive: Suppose s,t and r are strings. if sAt, and tAr, then since s and t have the same sum, and t and r have the same sum, s and r have the same sum. So sAr.