The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
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Answer:
A
Step-by-step explanation:
units like radius, height, width, length or segments are single units, like meter or feet.
areas are double units, so they'd be in say meter² or feet².
volumes are triple units, namely like meter³ or feet³.
The mode is the number repeated most often, so if we arrange these numbers in order, we can see what numbers repeat the most-
1 1 1 2 3 3 5 7 8 8 9
The number that repeats the most is 1
(1 counted 3 times)
(3 counted twice)
(8 counted twice)
Answer:
true
Step-by-step explanation:
sinA² + cosA²=1
⇔(1/2)² + cosA²=1
⇔cosA=±(√3/2)
