A) Variance = 10.24
B) Standard Deviation = 3.2
One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.
TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²
0 - 0.9 43 0.45 -3 9 -129 387
1.0 - 1.9 17 1.45 -2 4 -34 68
2.0 - 2.9 19 2.45 -1 1 -19 19
3.0 - 3.9 18 3.45 0 0 0 0
4.0 - 4.9 14 4.45 1 1 14 14
5.0 -5.9 16 5.45 2 4 32 64
∑f = 127
∑fd = -136
∑fd² = 552
Standard Deviation = 
√4.35 - √1.15
Standard Deviation = 3.2
(SD)² = (3.2)² = 10.24
Variance = 10.24
To know more about standard deviation, refer to this link :
brainly.com/question/12402189
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If only the fittest survive in certain enviorments other animals have to evolve to live in different places
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345%
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Median
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Hope this helped
A. Alyssa did not get an A on the math test but rather a B- due to only getting 16 out of the 20 problems right. This can be found out by dividing the amount correct over the total amount of problems.
B. In order for Alyssa to get an A or 90% on her math test she would have had to get two more questions right to have a score of 18 out of 20.
C. In order to figure this question out you have to think that with every incorrect answer that Jessie answered she got three correct along with the one incorrect. By going with that information it can be figured that Jessie's score is 15 correct answers and 5 incorrect information if you go by the ratio 3:1 then go up tell the sides equal up to a total of 20 after being added. So Jessie's score again was 15 out of 20.
