Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
true
Step-by-step explanation:
because the variable terms are in the left side of the equation and everything else in right side.
What are the 7 & 9 for? Obviously, you had info from somewhere else for the 9 & 7 if they are THE ONLY NUMBERS here
Answer:
CD = 24
Step-by-step explanation:
If G is the centroid, then CG = GD. (12 = 12)
Since CD is CG and GD combined, we would just add these two numbers to find the total length of CD.
CG + GD = CD
12 + 12 = 24
Answer:
and?
Step-by-step explanation:
