Answer:
well if the bottom two are 30 then that leaves you with 70
Step-by-step explanation:
Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.
<u>Solution:</u>
Let us assume that x is speed of slower eastbound cyclist
So, x+3 will be the speed of faster westbound cyclist
We know that distance is the product of speed and time. That is,

West-bound DATA:
Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles
East-bound DATA:
Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles
On solving,
Distance apart = 162



So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be 
Answer:
1) f(g(-2))=-3, 2) g(f(0))=5
Step-by-step explanation:
1)f(g(-2))
First, g(-2) means that x=-2. Hence, you must find the value of g(x) in the table when x=-2. You can see that, when x=-2, g(-2) = -3.
Next, you must find f(-3) in the graph, where x=-3. You can see in the graph that, when x=-3, f(-3) = -2.
Therefore, f(g(-2))=-3
2) g(f(0))
In the case, we must apply the inverse procedure. First, check in the graph that, when x=0, f(0) =1.
Next, we must look at the table and see that, when x=1, g(1)=5. Hence,
g(f(0))=5
30/78 simplified is 15/39