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2 years ago

6

For Howards science experiment he needs 69 blocks that each have a mass of 0.5 kilograms. Is the total mass of the blocks 3.45 k

ilograms, 34.5 kilograms, or 345 kilograms?

1 answer:

Andreas93 [3]2 years ago

6 0

34.5kg.
Just take 69 blocks and times by 0.5

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Miguel's cat, Chester, weighs 6.8 pounds. Chester's vet tells Miguel to feed the cat 3 4 of an ounce of canned food daily for ea

Vitek1552 [10]

Answer:

0.4 ounces

Step-by-step explanation:

In a day

Miguel is to feed Chester ,

Chester can eat 3/4 of an ounce for each pound of body weight.

Chester weighs 6.8 pounds

Hence:

1 pound = 3/4 ounce

6.8 pounds = x ounces

Cross Multiply

x = 6.8 × (3/4) ounces

x = 5.1 ounces

Chester is to be fed 5.1 ounces of food each day.

The amount of food left after 1 day

= 5.5 ounces - 5.1 ounces

= 0.4 ounces

Hence, 0.4 ounces of food is left after 1 day

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2 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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2 years ago

Find the measure of each angle indicated. HELPPP PLEASE

anzhelika [568]

Answer:

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Step-by-step explanation:

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At a glass vase store, 8 out of the last 20 vases shipped were chipped.

Juli2301 [7.4K]

Answer:

Step-by-step explanation: I have no idea

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3 years ago

A plane takes off and climbs steadily gor 30 minutes until it reaches 35,000 feet. It travels at that altitude for 2 hours until

horrorfan [7]

This is a function where:
x - time in minutes;
y = f ( x ) - altitude of a plane in feet.
Max altitude = 35,000 feet
0.5 h + 2 h + 15 min = 30 min + 120 min + 15 min = 165 min
Domain:
x ∈ [ 0; 165 ]
Range:
y ∈ [ 0; 35,000 ]

6 0

3 years ago