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2 years ago

In a group of 24 people, 10 study

Mathematics

2 answers:

Minchanka [31]2 years ago

8 0

Answer:

n = 24

p(a) = 10/24

p(b) = 15/24

[ p(a) + p(b) - [p(a) ×p(b)] ] -1 = answer

[ 35/24 - 6/24 ] -1 = 39/24 - 24/24 = 5/24

Ludmilka [50]2 years ago

8 0

<h3>Answer: 6</h3>

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Explanation:

There are 24 people total and 18 of them study at least one subject. So that must mean 24 - 18 = 6 people do not study any of the subjects mentioned.

The values of 10 and 15 aren't used at all.

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Help please! I don't really understand :/

hram777 [196]

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2 years ago

A number increased by fifteen is nineteen. A number increased by fifteen is nineteen.

elixir [45]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the system of equations 2 + 2y = -20 and x + 3y = -27 by combining the<br> equations.

AlexFokin [52]

Answer:

no estoy segura como se debe responder

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3 years ago

Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, then how much is his overall budg

Fynjy0 [20]

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1 year ago

Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0

cestrela7 [59]

When $n=0$ , you have

$4^0=1\equiv3(0)+1=1\mod9$

Now assume this is true for $n=k$ , i.e.

$4^k\equiv3k+1\mod9$

and under this hypothesis show that it's also true for $n=k+1$ . You have

$4^k\equiv3k+1\mod9$
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$\implies 4^{k+1}\equiv12k+4\mod9$

In other words, there exists $M$ such that

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Rewriting, you have

$4^{k+1}=9M+9k+3k+4$
$4^{k+1}=9(M+k)+3k+3+1$
$4^{k+1}=9(M+k)+3(k+1)+1$

and this is equivalent to $3(k+1)+1$ modulo 9, as desired.

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3 years ago