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3 years ago

Can 8/45 be simplified as a fraction

Mathematics

1 answer:

max2010maxim [7]3 years ago

8 0

Answer:

Step-by-step explanation:

isn't it already a fraction or is it a division

if it's a division then yes

the answer is 5 and 2/8

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A)<br> Identify all x-values not in the domain of<br> y=(x² – 4x²) / (3x² - 6x – 24)

True [87]

Answer:

x ≠ 4 or -2

Step-by-step explanation:

the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.

3x^2 - 6x - 24 ≠ 0

3(x^2 - 2x - 8) ≠ 0 (factor out a 3)

3(x - 4)(x + 2) ≠ 0 (factor equation)

x ≠ 4, x ≠ -2 (use zero product property to find zeros)

3 0

3 years ago

You have an allowance to spend on lunch this week. You will spend the same amount each day,and you get to keep whatever is left

Naily [24]

Answer:

The total allowance is $18.5, and the amount spent daily is $3.2

Step-by-step explanation:

let T and x represent the total allowance and the amount spent daily respectively.

It was started that the amount remaining after 2 days is $12.10 , which implies the person has spend an equal amount for 2 days

T - 2x =12.10 (equation 1)

It was started that the amount remaining after 5 days is $2.50 , which also implies the person has spend an equal amount for 5 days

T - 5x =2.5 (equation 2)

subtract equation 2 from 1

T - 2x -( T - 5x ) = 12.10 -2.5

T - 2x -T + 5x = 9.6

3x =9.6

Divide both side by 3

x = 9.6/3 =3.2

from equation 1

T - 2x =12.10

T = 12.10 + 2x = 12.10 + 2*3.2

= 12.10 + 6.4 = 18.5

5 0

3 years ago

Read 2 more answers

A videotape store has an average weekly gross of $1,158 with a standard deviation of $120. Let x be the store's gross during a r

statuscvo [17]

Answer:

The number of standard deviations from $1,158 to $1,360 is 1.68.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1158, \sigma = 120$