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3 years ago

Can the sides of a triangle have lengths 2,4, and 10? Yes or no

Mathematics

1 answer:

Luba_88 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

the length of the smaller sides have to add up to the length of the largest side

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Erica babysits for 4 ½ hours and is paid $27. How much does she make for 8 hours?

Shalnov [3]

Answer: $216

Step-by-step explanation:

Hope it helped

8 0

3 years ago

Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no

baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0

3 years ago

Sierra left $4.50 as a tip for a waiter. THis was 18% of the bull before the tip, How much was her total bill before the tip?

andreyandreev [35.5K]

let's say the bill without the tip is "x" amount, so that'd be the 100% of the bill, but we also know that 4.50 is the 18% of "x".

so if 4.50 is the 18% of "x", how much is "x"?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 4.50&18\\ x&100 \end{array}\implies \cfrac{4.5}{x}=\cfrac{18}{100}\implies 450=18x \\\\\\ \cfrac{450}{18}=x\implies 25=x$

4 0

3 years ago

Solve for x and y in the parallelogram

Lubov Fominskaja [6]

Answer:

x=3

y=6

Step-by-step explanation:

Hope this helps! :)

4 0

3 years ago

Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent

Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

$\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}$

$x$ represents each data, $\overline{x}$ is the mean and $n$ is the number of items. $x-\overline{x}$ is the deviation from the mean of each data item.

For the first data set, $\rho=\sqrt{6}=2.45$

For the second data set,

$\rho=\sqrt{45}=6.71$

The low value of $\rho$ for the first set indicates that the items are all closer to the mean than for the second set.

Variance is the square of the standard deviation. It could also be used.

7 0

3 years ago