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posledela
2 years ago
5

Can the sides of a triangle have lengths 2,4, and 10? Yes or no

Mathematics
1 answer:
Luba_88 [7]2 years ago
7 0

Answer:

no

Step-by-step explanation:

the length of the smaller sides have to add up to the length of the largest side

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If you invest $4000 at 9% interest compounded annually, in how many years will you have $20,000. Give your answer the nearest te
Masteriza [31]

Answer:

18.7 years

Step-by-step explanation:

This is a compound interest problem and the following variables have been given;

Principal = 4000; this is the amount o be invested

APR = 9%; this is the compound interest to be earned

Accumulated amount = 20,000

We are required to determine the duration in years. We apply the compound interest formula;

A=P(1+r)^{n}

20000=4000(1+\frac{9}{100})^{n}\\20000=4000(1.09)^{n}\\5=(1.09)^{n}

The next step is to introduce natural logarithms in order to determine n;

ln5=nln(1.09)\\n=\frac{ln5}{ln(1.09)}\\n= 18.675

The number of years required is thus 18.7 years

6 0
3 years ago
G(t)=(t+1) ^2-20.25 what are the zeros of the function
Vinil7 [7]

Step-by-step explanation:

g(t) = (t + 1)² − 20.25

0 = (t + 1)² − 20.25

20.25 = (t + 1)²

±4.5 = t + 1

t = -1 ± 4.5

t = -5.5 or 3.5

The zeros are (-5.5, 0) and (3.5, 0).

5 0
3 years ago
C) Write 2400 000 in standard form.
svp [43]

Answer:

2 400 000

Step-by-step explanation:

divide the numbers into 3

8 0
3 years ago
Read 2 more answers
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
HURRY PLEASE!!!<br> I WILL GIVE YOU BRAINLIEST!!
-Dominant- [34]

Answer:

Hope.you have a good merry Christmas Happy early new year

5 0
3 years ago
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