Answer:
They are SIMILAR triangles
Step-by-step explanation:
Given triangles MNL and FHG with two of their angles to be 51° and 36° respectively. Their third angle is expressed as:
180°-(51°+36°)
= 180°-87°
= 93°
Their third angle is 93°
Since both triangles have the same angles in them, both triangles are considered as similar triangle even though the value of their sides are different due to angle differences in both.
Note that individual triangles are scalene triangles since their angles are not the same but the both triangles are similar triangles based on their relationship.
Answer:
-1
Step-by-step explanation:
Given,
f(x) = -x² + 4x - 1 and x = 0
Putting the value of x we get,
f(0)=
+ (4 X 0) - 1
= -0+0-1
=-1
∴f(x)= -1
So, the required value is -1
<span>Premise
1: If a polygon was translated to the right, then its image is
congruent to its pre-image.
In symbols: p => q
Premise 2: If an image is congruent to its
pre-image, then a rigid transformation was performed.
In symbols: q => r
By the law of silogism
(p => q) and (q => r) => q => r
So, the conclusion is that </span><span>if a polygon was translated to the right, then a rigid transformation was performed. <---- answer</span>
Answer:
first off, when did Marge become a teacher
Step-by-step explanation:
Second off, he didn't flip the sign inside of the parentheses.
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min