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3 years ago

Identify the solutions of the inequality 11 ≤ p + 5.

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

<span>all real numbers greater than or equal to 6 </span>

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What is the quotient. Of 25)9250

saul85 [17]

Answer:

370

Step-by-step explanation:

Isolate the numbers so that you are only dividing sections at a time.

So 25 goes in to 92 three times. so we multiply 25 by three and subtract that from 92. Put the three at the top and repeat throughout.

92-75=17

Bring the next number down and repeat.

6 0

2 years ago

Read 2 more answers

Carla has already written 10 pages of a novel. she plans to write 15 additional pages per month until she is finished. write and

grin007 [14]

Linear Equation: 15m+10=w
15 pages written for every month for 5 months plus the 10 pages she has already written is equal to the total number of pages written in 5 months.
m= number months written. In this case, it is 5 months.
w= number of pages written in 5 months
15(5)+10=w
75+10=w
85 pages written=w
Carla will have written 85 pages in 5 months.

4 0

3 years ago

Which number is NOT in the solution set of x + 5 > 10?

Oksana_A [137]

x is greater than or equal to 6 so 5 and below are not a solution to this inequality.

6 0

3 years ago

The two dot plots below compare the forearm lengths of two groups of schoolchildren:

Angelina_Jolie [31]

Answer:

Group A, because seven children have a forearm length longer than 10 inches

Step-by-step explanation:

Create the dot plots based on the given information (please see attached images).

Group A = blue dots

Group B = red dots

From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length. This is because 7 children have a forearm length of longer than 10 inches.

To calculate the average forearm length, sum all data values and divide by the total number of data values.

$\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11$

$\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9$

Thus proving that Group A has the longer average former length.

7 0

1 year ago

Read 2 more answers

A license plate consists of two letters followed by two digits; for example, $MP78$. Neither the digits nor the letters may be r

alex41 [277]

If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.

Given that a number plate can be formed using 2 alphabets which must come in increasing order.

We are required to find the number of plates that can be formed.

Number of total alphabets=26.

The number of plates will be equal to the number of ways in which two alphabets can be arranged.

Combination is the number of ways in which some combinations can be formed. It is expressed as n $C_{r}$ =n!/r!(n-r)!

Number of license plates=26 $C_{1}$ *25 $C_{1}$

=26*25

=650 plates

Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.

Learn more about combinations at brainly.com/question/11732255

#SPJ4

3 0

1 year ago