2 years ago

Joseph ran a 6 mile race and 48 minutes which graph has a slope that best represents the average rate of speed during the race

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

4 0

Answer:

Step-by-step explanation:

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Alex has 235 candies. He wants to place the candies in five equal groups. How many candies will Alex place in each group?

Bad White [126]

Answer:

A.47

Step-by-step explanation:

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2 years ago

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Peter left city a at 9:00 am towards city b at an average speed of 50 mph. Thirty minutes later Emily also leaves city a towards

Archy [21]

Answer:

62.5 mph

Step-by-step explanation:

Given that :

Peter :

Speed = 50mph

Start Time = 9 a. M

Emily :

Start time = 9:30

Speed = x

In other to catch up at 11:30 :

Peter (11:30 - 9:00) = 2hours 30 minutes = 2.5 hrs

Total distance moved by Peter :

Speed * time = 50 * 2.5 = 125miles

For Emily to cover 125 miles in (11:30 - 9:30) = 2 hours

Speed = distance / time

Speed = 125 miles / 2 hours

Speed = 62.5 miles per hour

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2 years ago

Answer the photo below thanks <br> Question: What is the value of x in the diagram.

kaheart [24]

Answer:

A. X = 30º

Step-by-step explanation:

The angle labeled x & the right angle are vertical angles to the one labeled 120º.

Therefore:

X + 90 = 120

Solve for x:

X + (90-90) = 120 - 90

X = 30

Hope this helps! Have a great day!

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3 years ago

mafiozo [28]

Answer:

A, B and D

Step-by-step explanation:

Because all of these are true

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2 years ago

Newton’s law of universal gravitation, F=Gm1m2/r²,measures the force of gravity between two masses m1 and m2,where r is the dist

Pavel [41]

Answer:

$G=\frac{Fr^2}{m_1m_2}$

Step-by-step explanation:

Since our equation is $F=\frac{Gm_1m_2}{r^2}$ and we want to solve for G, first we divide both sides by the product $m_1m_2$ , which gives:

$\frac{F}{m_1m_2}=\frac{Gm_1m_2}{m_1m_2r^2}=\frac{G}{r^2}$

So we are left with:

$\frac{F}{m_1m_2}=\frac{G}{r^2}$

Now we multiply both sides by $r^2$ , which gives:

$\frac{Fr^2}{m_1m_2}=\frac{Gr^2}{r^2}=G$

Which gives us our final formula:

$G=\frac{Fr^2}{m_1m_2}$

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3 years ago