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max2010maxim [7]

3 years ago

6

how is building a triangle with different side lengths given different than building a quadrilateral with given side lengths?

1 answer:

Mariana [72]3 years ago

8 0

Answer:

there can only be one possibility for a triangle when given the lengths of all the sides but for a quadrilateral the measure of the angles could differ depending on the person building the,. this is because triangles are more stable than quadrilaterals meaning that their side lengths follow a lot more rules than quadrilaterals do, for example the length of the side lengths can indicate whether or not that triangle is an acute, obtuse, or right triangle, and this is also evident by considering that you can use the SSS theorem to indicate two triangles are congruent, but for quadrilaterals you cant do that

Step-by-step explanation:

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What’s the answer? Please help

blsea [12.9K]

Answer:

B

Step-by-step explanation:

Since you are trying to find out half the number of students in a PE class, dividing would be most appropriate since you would be trying to find half.

4 0

2 years ago

-2 (t+2) +5 t = 6 t + 11

vovikov84 [41]

Answer:

The answer is T=-5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

3 years ago

Read 2 more answers

Violin strings are parallel. Viewed from above, a violin bow in two different positions forms two transversals to the violin str

svlad2 [7]

ANSWER

$x=10$

and

$y=20$

EXPLANATION

Since corresponding angles are equal,

$4x+y=60---(1)$

Alternate angles are also equal, therefore,

$8x+y=100---(2)$

Equation (2) minus equation (1) gives,

$\Rightarrow 4x=40$

$\Rightarrow x=10$

We put $x=10$ in to equation (1)

$4(10)+y=60$

$y=60-40$

$y=20$

4 0

3 years ago

Look at the right-angled triangle ABC.

olga_2 [115]

Answer:

∠x = 90°

∠y = 58°

∠z = 32°

Step-by-step explanation:

he dimensions of the angles given are;

∠B = 32°

Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;

∠A = 90°

∠B + ∠C = 90° which gives

32° + ∠C = 90°

∠C = 58°

∠x + Interior angle of the square = 180° (Sum of angles on a straight line)

∠x + 90° = 180°

∠x = 90°

∠x + ∠y + 32° = 180° (Sum of angles in a triangle)

90° + ∠y + 32° = 180°

∠y = 180 - 90° - 32° = 58°

∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)

58° + ∠z +90° = 180°

∴ ∠z = 32°

∠x = 90°

∠y = 58°

∠z = 32°

8 0

2 years ago