how is building a triangle with different side lengths given different than building a quadrilateral with given side lengths?
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<span>Let the distance from A to the ends of the lake be w and r . From the given it appears that
w / sin 104 = 136 / sin 56 and r / sin 120 = 136 / sin 15....solve for w & r.
then L² = r² + w² - 2 r w cos 65 , where L = length of the lake...
attached a picture
</span>
w / sin 104 = 136 / sin 56 and r / sin 120 = 136 / sin 15....solve for w & r.
then L² = r² + w² - 2 r w cos 65 , where L = length of the lake...
attached a picture
</span>
boys (b): b
girls (g): b + 100
total (T) = b + g
I am going to set up the proportion as "boys" to "total"
⇒
⇒ 3(2b + 100) = 10(b)
⇒ 6b + 300 = 10b
⇒ 300 = 4b
⇒ 75 = b
girls (g): b + 100 = (75) + 100 = 175
Answer: boys = 75, girls = 175